Comment summary #32
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Comment 311 ... 320
| date | article | author | comment |
| 16 feb 2016 23:16:22 | Arduino wattmeter | Freddy | These display modules can be used in parallel. Only the "E" lines, who select which display to communicate with, must be connected separately on the Arduino. You have to write your own code because it's to much work for a specific case. Yes, you could make selectable ranges, but it would make it a completely different design. Implementing selectable ranges was also my first idea. But I was advised not to do so, because it would make the circuit to complicated for less experienced people. And those were the people who I had in mind when I designed this DIY wattmeter. |
| 16 feb 2016 23:00:55 | Arduino wattmeter | Wolfram Fischer | Hi, would it be much work if you make a 2nd CS for a 2nd 2x16 LCD? I can't use a 4x16, just want to use 2 peaces of 2x16 LCDs! As i Can see are A0 to A4 still unused. That would be great! And a second question/Request: How about using a switch and a free input to switch a voltage range from 50V to 500V (and switch the float Vdiv = 101.0; // Voltage conversion factor float Cdiv = 10.0; // Current conversion factor depending on that free input) for a lo/hi range? Or autorange with an free io... if v>50 digitalout(A2),High and switch a relays? |
| 15 feb 2016 11:10:11 | Arduino wattmeter | Freddy | I never tried it, but I think u can use the analog inputs A0...2 instead of A4...6 by changing ADMUX = muxCnt | 0xC4; into ADMUX = muxCnt | 0xC0; in ISR(ADC_vect) ,the ADC interrupt routine. You can change the initial parameter for each line in: byte paramPointers[4] = {0,7,13,18}; These point to the parameter list in: char* paramLabels[] at the line below. |
| 14 feb 2016 16:31:02 | Arduino wattmeter | angel | I wish to change the input channel for the voltage, current and COM to the analog pins 1, 2, 3 of the nano respectively (instead of 4, 5, 6). I tried changing ADMUX in the initiateADC function of your code to 0xC1 instead of 0xC4, but i still can't use channels 1, 2, 3. Also, i only want to display Vrms, Irms and Preal. I do not want to use a push button. |
| 11 feb 2016 07:29:03 | Arduino wattmeter | Allan Lind | If your opamp is inverting and has a gain of 10 and you put +1V in you would only get -10V if you had a +/- 12V supply! As you only have a single +5V supply the opamp will saturate and swing to the minus rail, which will be close to 0V. Even though the opamp is a Rail To Rail type it still cannot quite get to 0V hence your 0.1V reading. Try reducing the input to keep the opamp output within it's supply rails which will be 0.1V ~ 4.9V (with respect to ground). |
| 10 feb 2016 10:52:03 | Arduino wattmeter | Allan Lind | Depends where you are referencing your input and output voltages. Keep in mind the reference point "A6 COM" is not at 0V. It is floating somewhere between 0V and 5V, connected to a voltage divider comprising 2k2 and 270Ohm resistors. So it will be at 5*(270/(270+2200) = 0.547V |
| 10 feb 2016 09:43:43 | Arduino wattmeter | Azzelle | I used the LTC1050 to build an inverting amplifier. The source resistor is 1KOhm and the feedback resistor is 10KOhm. The input I use is 1V and get the ouput of 0.1V. Based on my calculations, I should get an output of 10V. Does the LTC1050 have an internal amplification? |
| 05 feb 2016 23:20:12 | Arduino wattmeter | A. Catena | Fantástico circuito Freddy. Quiero hacerlo para 220V - 20A AC/DC. El medidor indica si la entrada es AC o DC, indica la polaridad + y - ?. Muchas gracias Freddy por compartir, soy estudiante de electrónica y este circuito me enseña mucho, muchas gracias. Saludos. |
| 28 jan 2016 20:38:14 | Arduino wattmeter | Allan Lind | Awesome! I will build one for New Zealand/Australia/UK single phase household main 230VAC 50Hz 60A but using a split core CT to Isolate the current and enable use of a smaller shunt. I am thinking to add a transmitter so that the data is available in another location. Now to look for a suitable clamp. |
| 28 jan 2016 11:29:43 | Arduino wattmeter | Freddy | Yes, the power meter measures both positive and negative values depending on the power flow direction. |